Math, asked by deadshot43, 1 year ago

2 tan 30°
 \div

1 -tan 30°
(A)
cos 60°
(B) sin 60
(C) tan 60°
(D) sin 30°
please ans this question in full basic manner please.................​

Answers

Answered by BrainlyPopularman
1

Answer:

 \frac{2 \tan( {30}^{0} ) }{1 -  \tan( {30}^{0} ) }  =   \frac{ \frac{2}{ \sqrt{3} } }{1 -  \frac{1}{ \sqrt{3} } }  =  \frac{2}{ \sqrt{3}  - 1}

None of these

Answered by KUMAR55RISHU
1

Answer:

because, tan2A=2tanA/1-tan^2A

therefore, 2tan30°/1-tan^2 30°=tan 2×30°=tan60°.

this is your answer.

please mark as brainliest.

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