Question

2 tan 45 degree /1+tan square 45 degree​

Answer 1

Given :

$\frac{2tan45}{1 + tan^{2} 45}$

To Find :

The value of $\frac{2tan45}{1 + tan^{2} 45}$

Solution :

$\frac{2tan45}{1 + tan^{2} 45}$

= $\frac{2 * 1}{1 + 1}$  ( tan45° = 1)

= $\frac{2}{2}$

= 1 (Answer)

What are Trigonometric Functions?

The relationship between the angles and sides of a triangle are given by the trigonometric functions.

Answer 2

$\displaystyle \sf{ \frac{2 \: tan \: {45}^{ \circ} }{1 + {tan}^{2} \: {45}^{ \circ}} = 1 }$

Given :

$\displaystyle \sf{ \frac{2 \: tan \: {45}^{ \circ} }{1 + {tan}^{2} \: {45}^{ \circ}} }$

To find : The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{ \frac{2 \: tan \: {45}^{ \circ} }{1 + {tan}^{2} \: {45}^{ \circ}} }$

Step 2 of 2 :

Find the value of the expression

$\displaystyle \sf{ \frac{2 \: tan \: {45}^{ \circ} }{1 + {tan}^{2} \: {45}^{ \circ}} }$

$\displaystyle \sf{ = \frac{2 \times 1}{1 + {1}^{2} } }$

$\displaystyle \sf{ = \frac{2 }{1 +1 } }$

$\displaystyle \sf{ = \frac{2 }{2} }$

$\displaystyle \sf{ = 1 }$

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