2 tan A tan B = 1 find cos(A-B)/cos(A+B)
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Answered by
2
Answer:
Given that 2tanA. tanB=1 or tanA.tanB=1/2
Now cos(A-B) / cos(A+B)
= (cosA.cosB+sinA.sinB) / (cosA.cosB-sinA.sinB)
Divide cosA. cosB
=(1+tanA.tanB) / (1-tanA.tanB)
=(1+(1/2) ) / (1-(1/2) )
=3
Answered by
0
Answer:
Given
2tanA. tanB=1
tanA.tanB=1/2
cos(A-B) / cos(A+B)
= (cosA.cosB+sinA.sinB) / (cosA.cosB-sinA.sinB) Divide by cosA. cosB
=(1+tanA.tanB) / (1-tanA.tanB)
=(1+(1/2) ) / (1-(1/2) )
=3
Step-by-step explanation:
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