Question

2 tan inverse 1/3+sin inverse 4/5

Answer 1

sin^-1 (4/5)=tan-1 (3/4)
2tan^(-1) (1/3)+tan^(-1) (3/4)
tan^-1 ((2/3/8/9) +tan^(-1)(3/4)
tan^-1 (3/4)+tan^-1 (3/4)
=2tan^(-1) (3/4)

Answer 2

ans is here.............