Question

2 tan
sin e
50 + 5 cos- 90
cot 30
Mar. 16 (TS)
in the given
ne '16 TS
sine = 4 (0ocos.
sec 30-
3
0 (1 - Cos 0)
sin e
11. 111- cos 1 + cos O + (0 so
then find
en find the value of o. June
sin o sin
Sol. 1- cos O 1 + cos e
sine (1 + cos O) + sin 0 (1 -
(1 - cos 0) (1 + cos 0)
sin e + sin ecos e + sin 0 cosa
1-cos²0
20 60=2
os? 90 =
2 sin 0 - 4
(:: 1 - cos? O = sin
.
2 0 = sino
= 4
sin’e
2
= 4 = sin 0 = 3 = sin 300
5(0)2
sin e
0 = 30° explain answer​

Answer 1

Answer:

u have done the correct answer of is the right path but ghe differance is only that of the use of identity

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