2 + tan theta/2 cosec theta + sec theta
Answers
Answered by
1
Answer:
let theta = α
then, (2 + tan α) / (sec α + 2cosec α)
= (2 + sinα/cosα) / (1/cosα + 2/sinα)
= (2cosα + sinα)/cosα / (sinα + 2cosα)/(sinα)(cosα)
= (2cosα + sinα)/cosα x (sinα)(cosα)/(sinα + 2cosα)
= (sinα)(cosα) x 1/cosα
= sin α
Step-by-step explanation:
follow me plz...
Answered by
3
Step-by-step explanation:
the above attachment helps you....
Attachments:
Similar questions