Question

2 + tan theta/2 cosec theta + sec theta
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Answer 1

Answer:

let theta = α

then, (2 + tan α) / (sec α + 2cosec α)

= (2 + sinα/cosα) / (1/cosα + 2/sinα)

= (2cosα + sinα)/cosα / (sinα + 2cosα)/(sinα)(cosα)

= (2cosα + sinα)/cosα x (sinα)(cosα)/(sinα + 2cosα)

= (sinα)(cosα) x 1/cosα

= sin α

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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