2 tan theta - cot = -1
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Answer:
Ф = n π + π / 4 where n ∈ I
Explanation:
2 tan Ф - cot Ф = 1 [ Using cot x = 1 / tan x ]
2 tan Ф - 1 / tan Ф = 1
2 tan² Ф - 1 = tan Ф
2 tan² Ф - tan Ф - 1 = 0 [ Applying quadratic formula ]
tan Ф = 1 ± √ 1 + 8 / 4
tan Ф = 1 ± 3 / 4
Case 1 .
tan Ф = 1 + 3 / 4
tan Ф = 4 / 4
tan Ф = 1
tan Ф = tan π / 4
Ф = n π + π / 4 where n ∈ I
Case 2 .
tan Ф = 1 - 3 / 4
tan Ф = - 2 / 4
tan Ф = - 1 / 2
This case is not possible .
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