Math, asked by rituwalia874, 1 month ago

2 tan²60+4sin^60-2tan^30xsec^30/
2sin ^45-5sin90 + 3cos^90- 6 cos 60​

Answers

Answered by manya5522
0

Step-by-step explanation:

2tan^2 60°+4 sin^2 60-2tan ^2 30°× sec^2 30°÷2 sin^2 45° - 5 sin 90°+3 cos ^2 90°-6cos 60°

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