2 tan30/1+tan30 solve
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By substituting the values of given trigonometric ratios in the above equation, we get
= 2 × (1/√3)/1 + (1/√3)2
= 2 × (1/√3)/(1 + 1/3)
= (2/√3) / (4/3)
= 6/4√3
= √3/2
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