2 tan45° + cos 45° - San 45°
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Answered by
1
Answer:
tan 45°=1
cos 45°=1/√2
sin 45°=1/√2
2tan45°+cos45°-sin45°= 2×1+1/√2-1/√2
=2+(1/√2-1/√2)
= 2(1-1/√2)
=2+0
=2
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