Question

2 tan57÷cot33-cot70÷tan20- √2 cos45

Answer 1

2tan57cot33-cot70tan20-2cos45=2tan57cot90-57-cot90-20tan20-2cos45=2tan57tan57-tan20tan20-2×12=2-1-1=0⇒2tan57cot33-cot70tan20-2cos45=0

Answer 2

Answer:

0

Step-by-step explanation:

=2tan57°/cot(90-57)-cot70°/tan(90-70)-√2cos45°

=2tan57°/tan57°-cot70°/cot70°-√2cos45°

=2-1-√2(1/√2)

=1-1

=0