2 taps opened into a tank, if we turn on both tapes . The tank would be filled in 12min. Time taken to fill the tank by the smaller tap alone take 10 min more than the time taken by the bigger tap. If the smaller tap is opened , what would be the time to fill the tank
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Step-by-step explanation:
My name is Abhinav.
Explanation:
Let the time taken by bigger tap be 'x',
Let the time taken by smaller tap be 'y'.
Time time taken by both tap is equal to
- x+y=12
When we start both tap seperately.
When we start both tap seperately. smaller tap means 'y' so equation comes
x=y+10
x-y=10
By elimination method
x+y=12
x-y=10
2x=22
x=11
There fore by putting value of x=11
in x-y=10
11-y=10
-y=10-11
-y=-1
y=1
Therefore smaller tap takes 1
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