Math, asked by varsharaut7887, 1 day ago

2. Ten years ago, A's age was half of B's age. If the ratio of their present ages is 3:4, what will be the sum of their present ages ? ​

Answers

Answered by Saachishinde1609
0

Answer:

35 years

Step-by-step explanation:

B/Q:-

3x-10= 1/2(4x-10)

2(3x-10)= 2x-5

3x-10= 2x-5

x= -5+10

x= 5

A's age= 3X5= 15

B's age= 4X5= 20

Sum of their ages= 15+20= 35 years.

Answered by anita16jangid
0

Step-by-step explanation:

Hi

I hope this helps

pls mark me as a brainlist

Attachments:
Similar questions