2) Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B?
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Step-by-step explanation:
so let ages of a and b be x and y years
so according to first case,
(x+10)=2(y+10)
so x+10=2y+20
ie x=2y+10 (1)
according to second case
x-5=3(y-5)
x-5=3y-15
ie x-3y=-10 (2)
substitute value of x from (1) in (2)
we get
2y-3y=(-10-10)
ie -y=-20
so y=20
substitute it in (1)
we get
x=50
hence presently A is 50 years old and b is 20 years old
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