Math, asked by aravvishal, 6 months ago

2. Test the divisibility of the following numbers by 3
(1) 733
(ii) 10038
(iv) 524781
(v) 79124
(iii) 20701
(vi) 872645
bibility of the following numbers by G​

Answers

Answered by vishu6975
5

Answer:

divisibility by 3 is

733 = 7+3+3= 13

it is not divisible by 3 because 13 is not at multiple of 3

Answered by akshhh88
3

Answer:

The divisibility rule by 3 for a number is-

If the sum of the digits of the number is divisible by 3, then the number is divisible by 3.

(i)733

Here, the sum of the digits is 13. But 13 is not divisible by 3.

Conclusion: 733 is not divisible by 3.

(ii)10038

Here, the sum of the digits is 12 and it is divisible by 3.

Conclusion: 10038 is divisible by 3.

(iii)524781

Here, the sum of the digits is 27 which is divisible by 3.

Conclusion: 524781 is divisible by 3.

(iv)79124

Here, the sum of the digits is 23 which is not divisible by 3.

Conclusion: 79124 is not divisible by 3.

(v)20701

Here, the sum of the digits is 10 which is not divisible by 3.

Conclusion: 20701 is not divisible by 3.

(vi)872645

Here, the sum of the digits is 32 which is not divisible by 3.

Conclusion: 872645 is not divisible by 3.

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