Question

2$2x^{2} +5x+7=2$

Answer 1

$<marquee scrollamout=1300>ANSWER✍✍</marquee>$

${22x}^{2} + 5x + 7 = 2$

$x(22x + 5) + 7 = 2$

$\frac{1936}{415} (x + \frac{5}{4} {)}^{2} = - 1$

${22x}^{2} + 5x + 5 = 0$

$22(x + \frac{5}{44} {)}^{2} + \frac{415}{88} = 0$