Question

2
$2x ^{2} + 7x + 5$
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Answer 1

$\tt{\purple{\underline{\huge{Answer:}}}}$

$:\implies{2x}^{2} + 7x + 5 = 0$

$:\implies {2x}^{2} + 5x + 2x + 5 = 0$

$:\implies \: x(2x + 5) + 1(2x + 5) = 0$

$:\implies(x + 1) = 0,(2x + 5) = 0$

$:\implies \: x = - 1,2x = - 5$

$:\implies \: x = - 1,x = - \dfrac{5}{2}$

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Answer 2

ANSWER✔

$\sf\therefore 2x ^{2} + 7x + 5=0$

$\sf\implies 2x^2+5x+2x+5=0$

$\sf\implies x(2x+5)+1(2x+5)=0$

$\sf\implies (x+1)(2x+5)=0$

$\sf\implies x+1=0,2x+5=0$

$\sf\implies x=-1,2x=-5$

$\sf\implies x=-1,x= \dfrsc{5}{2}$

$\sf\implies x=-1, \dfrac{5}{2}$

$\large{\boxed{\bf{ \star\:\: x=-1, \dfrac{5}{2}\:\: \star}}}$

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