Question

2
$2x ^{2} + 9x + 10$
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Answer 1

Answer:

Step-by-step explanation:

$2x^{2}+9x+10$

$2x^{2}+5x+4x+10$

$x(2x+5)+2(2x+5)$

$(x+2) +(2x+5) =0$

So, x+ 2= 0 or 2x + 5 = 0

x = -2 or x = -2.5

Hope this helps

Answer 2

Answer:

$= > 2x {}^{2} + 9x + 10 = 0 \\ = 2x {}^{2} + 4x + 5x + 10 = 0 \\ = > 2x(x + 2) + 5(x + 2) = 0 \\ = > (2x + 5)(x + 2) = 0 \\ = > x + 2 = 0 \\ = > x = - 2 \\ or \\ = > 2x + 5 = 0 \\ = > 2x = - 5 \\ = > x = - \frac{5}{2} \\ \\ = > hence \: \:( x = - 2 \: and \: - \frac{5}{2} )$