Question

2
$\sqrt{2} x {}^{2} - 3x - 2 \sqrt{2} = 0$
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Answer 1

Answer:

here it is

√2x^2-3x-2√2=0

then

after factorisation

√2x^2-4x+x-2√2=0

√2x(x-2√2)+1(x-2√2)=0

(√2x+1)(x-2√2)=0

x=-1/√2

x=2√2

ok

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Answer 2

Step-by-step explanation:

Answer is in the pic.

Hope it will help you!