Math, asked by sudharsan1, 1 year ago

2 \sqrt[n]{x}  \sqrt{x}

Answers

Answered by Gun
0
=  2 *  x^{1/n} *  x^{1/2}
= 2 *  x^{(n+2)/2n}
Answered by Anonymous
0
2 \sqrt[n]{x}  \sqrt[n]{x}  \\

 2x^{1/n +1/2}  \\

2 x^{(2 + n)/2n}


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