Question

(2) The 10th and the 18th terms of an A.P. are 25 and 41 respectively.
Find the 14th term of this A. P.
(i) Use the formula 1,= a + (n - 1)d.
(ii) From the given values of 10th and 18th terms form two equations.
(iii) Add these equations and find the value of the 14th term.​

Answer 1

Answer:

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Answer 2

Answer:

Thus 14th terms=33

Step-by-step explanation:

Let the first term is a and d is the commn diff

A1=a(n-1)d

then

A10=a+(10-1)d

25=a+9d...........(1)

and

A18=a+(18-1)d

41=a+17d..................(2)

adding eqn (1) and (2)

66=2a+26d

dividing both sides by2

33=a+13d

=a+(14-1)d

Thus A14=33

Thus 14th terms=33