Question

2) The 17th term of an A.P. is 14 more than its 10th term. Find the common difference.​

Answer 1

Answer:

a17=a10+14

a+16d=a+9d+14

a+16d-(a+9d)=14

a+16d-a-9d=14

7d=14

d=2

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Answer 2

The common difference is 2.

Step-by-step explanation:

Given : The 17th term of an A.P. is 14 more than its 10th term.

To Find : The common difference ?

Solution :

The nth term of an A.P is $a_n=a+(n-1)d$.

According to question,

$a_{17}=a_{10}+14$

i.e. $a+(17-1)d=(a+(10-1)d)+14$

$a+16d=(a+9d)+14$

$a+16d-(a+9d)=14$

$a+16d-a-9d=14$

$7d=14$

$d=\frac{14}{7}$

$d=2$

Therefore, the common difference is 2.

#Learn more

In an A.P. 17th term is 7 more than its 10th term. Find the common difference.

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