Question

2.
The absolute refractive index of glass is 4/3. What is its critical angle?
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Answer 1

GivEn :

• μ = 4/3

To FiNd :

• Critical Angle

SoluTion :

$\longrightarrow \tt{\mu\ =\ \dfrac{1}{\sin C}} \\ \\ \\ \longrightarrow \tt{\dfrac{4}{3}\ =\ \dfrac{1}{\sin C}} \\ \\ \\ \longrightarrow \tt{\sin C\ =\ \dfrac{3}{4}} \\ \\ \\ \longrightarrow \underline{\boxed{\mathfrak{C\ =\ sin^{-1} \bigg( \dfrac{3}{4} \bigg) }}}$

Answer 2

Explanation:

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