2. The age of the father is three times the sum of ages of his two children. After 5 years, his
age will be two times the sum of the ages of his children. Find the present ages of the
father
Answers
Answer:
Step-by-step explanation:
A father’s age is three times the age of his two sons. After 5 years, his age will be twice the sum of the ages of his sons. What is the age of the father?
Answer : Let the age of the sons be x and y.
Given that Father’s age is three times the age of his two sons.
Therefore, present age of father is 3(x+y)
Now, it is also given, after 5 years, his age will be twice the sum of the ages of his son.
Therfore, after 5 years age of father will be 3(x+y)+5 and age of the sons will be x+5 and y+5.
3(x+y)+5 = 2(x+5+y+5)
3x+3y+5 = 2x+10+2y+10
3x+3y+5 = 2x+2y+20
3x-2x+3y-2y = 20–5
x+y = 15
Now the age of father was 3(x+y)=3(15)=45 (Putting the value of x+y)
Thus the age of the father is 45.
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- Age of the father is three times the sum of ages of his two children.
- After 5 years, his age will be two times the sum of the ages of his children.
- What is the present age of Father ?
Let the present ages of children be 'x' and 'y' years
⁂ Sum of ages of his two children = (x + y) years
CASE:- 1)
➣ Age of the father is three times the sum of ages of his two children.
- Age of Father = 3(x + y) years
CASE:- 2)
➣ After 5 years, his age will be two times the sum of the ages of his children.
- Father's age = 3(x + y ) + 5 years
- Sum of ages of two children = (x + 5 + y + 5) years
【Father's age = 2(Sum of ages of children)】
➜ 3(x + y) + 5 = 2(x + y + 10)
➜ 3x + 3y + 5 = 2x + 2y + 20
➜ 3x + 3y –2x –2y = 20 –5
➜ x + y = 15
⁂ Sum of ages of his two children = 15
⁂ Father's age = 3(x + y)
➜ Father's age = 3 15
❝ Hence, the age of Father is 45 years ❞