Math, asked by rahulkrsingh1999, 1 month ago

2. The annual demand for an item is 32000 units. The unit cost is Rs. 6 and inventory carrying
charges 25% per annum. If the cost of one procurement is Rs. 150 and no shortages are
allowed, then find the number of orders per year and the minimum total inventory cost​

Answers

Answered by padiisgr8
1

Answer:

EOQ (Economic Order Quantity) = 800 units

No of orders per year = 4 orders per year

Time between two consecutive order = 3 months

Explanation:

Given :

• Annual demand (D) = 3,200 units

• Cost of one order (S) = Rs. 150

• Cost per unit (C) = Rs. 6

• Holding Cost in % (I) = 25%

• Holding Cost in Rs. (H) = I × C

To find :

• Calculate EOQ (Economic Order Quantity) = Q

• No of orders per year

• Time between two consecutive order

Solution :

Holding Cost (H) = I × C

\longrightarrow{\sf{6 \times \dfrac{25}{100}}}⟶6×10025

\longrightarrow \:  1.5⟶ 1.5

Holding Cost (H) = 1.5

★ EOQ :

\sf{\longrightarrow{Q={\sqrt{ \dfrac{2SD}{H}}}}}⟶Q=H2SD

\sf{\longrightarrow{Q={\sqrt{ \dfrac{2 \: \times \: 150 \: \times \: 3,200 }{1.5}}}}}⟶Q=1.52×150×3,200

\sf{\longrightarrow{Q={\sqrt{\dfrac{9,60,000}{1.5}}}}}⟶Q=1.59,60,000

\sf{\longrightarrow{Q={\sqrt{6,40,000}}}}⟶Q=6,40,000

\longrightarrow⟶ Q = 800 units

EOQ (Economic Order Quantity) = 800 units

★ No of orders per year :

\sf{\longrightarrow{\dfrac{Annual \: demand }{EOQ}}}⟶EOQAnnualdemand

\sf{\longrightarrow{\dfrac{3200}{800} \: = \: 4}}⟶8003200=4

No of orders per year = 4 orders per year

★ Time between two consecutive order :

\sf{\longrightarrow{\dfrac{EOQ }{Annual \: demand} \times \: Time}}⟶AnnualdemandEOQ×Time

\sf{\longrightarrow{\dfrac{800}{3200} \times \: 12 \: = \: 3}}⟶3200800×12=3

Time between two consecutive order = 3 months

Therefore,

EOQ (Economic Order Quantity) = 800 units

No of orders per year = 4 orders per year

Time between two consecutive order = 3 months

Answered by sakshijaan408
0

Answer:

from 16 whole 2/3m long ribbon,3/8part is cut off.it is further divided into 5 equal pieces, then find the length of each pieces

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