2. The area of a parallelogram is 406 sq.cm. Its height is
14 cm. Find the length of one of its sides.
Answers
Answered by
1
Step-by-step explanation:
Area of parallelogram= 406sq.cm
area of parallelogram=base X height
A/q
Height= 14 cm
406sq.cm = base X 14 cm
base= 406sq.cm/14 cm
base= 29 sq.
Answered by
0
AnSwEr -:
Base of parallelogram = 29 cm
______________________________
Area of parallelogram =
“B x h”
Here ,
B= base
H= height
_____________________________
Given ,
Area of parallelograms-: 406 sq. cm =
“b x h”
Base = ?? = b
Height = 14 cm = h
= 14 cm x b = 406 sq.cm
= b = 406 / 14
= b = 29 cm
Base of parallelogram = 29 cm
___________________________
Verification-:
Area of parallelogram =
B x h
Base = 29 cm = b
Height = 14 cm = h
Area of parallelograms-: 406 sq. cm
29 x 14 = 406 sq. cm
406 = 406
LHS = RHS
Hence verified
_______________________________
Base of parallelogram = 29 cm
______________________________
Area of parallelogram =
“B x h”
Here ,
B= base
H= height
_____________________________
Given ,
Area of parallelograms-: 406 sq. cm =
“b x h”
Base = ?? = b
Height = 14 cm = h
= 14 cm x b = 406 sq.cm
= b = 406 / 14
= b = 29 cm
Base of parallelogram = 29 cm
___________________________
Verification-:
Area of parallelogram =
B x h
Base = 29 cm = b
Height = 14 cm = h
Area of parallelograms-: 406 sq. cm
29 x 14 = 406 sq. cm
406 = 406
LHS = RHS
Hence verified
_______________________________
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