Question

2. The area of a rhombus is 16 cm2 and the length of one of its diagonals is 4 cm. Calculate the length of other the diagonal.

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Answer 1

$\bigstar \underline{\underline{\mathfrak{Given:-}}}$

• Area of rhombus =16cm².
• Length of one of it's diagonal=4cm.

$\bigstar \underline{\underline{\mathfrak{To\ find:-}}}$

Length of other diagonal.

$\bigstar \underline{\underline{\mathfrak{Solution:-}}}$

We know :

❥ Area of a rhombus = 1/2 ×(product of diagonals)

Let another diagonal be 'x'.

Acc to question :

$:\implies \sf Area=\frac{1}{2} \times (x)(4)\\\\:\implies 16=\frac{1}{2} \times (x)(4)\\\\:\implies 16 = 2x\\\\:\implies x=\frac{16}{2} =8\\\\:\implies \sf \boxed{\boxed{\bold{x=8cm.}}}$

Therefore, length of another diagonal is 8cm.

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✨ Know More :-

Properties of rhombus :

All sides of the rhombus are equal.

The opposite sides of a rhombus are parallel.

Opposite angles of a rhombus are equal.

Diagonals bisect each other at right angles.

The sum of two adjacent angles is equal to 180 degrees.

Perimeter = 4a.(Where 'a' is the side)

There can be no circumscribing circle.

There can be no inscribing circle.

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HOPE IT HELPS !

Answer 2

Area of rhombus = 16 cm^2, One diagonal = 4 cm. The other diagonal = 16*2/4 = 8 cm.