Question

2) The area of a right angled triangle is 27sqom and longer side
(perpendicular) is 3cm more that the base Find the hypotenuse
hey mates please help
correct one will be marked as branliest​

Answer 1

Step-by-step explanation:

As perpendicular is 3 more than base

so let base be x then perpendicular will be x+3

as by area of right angle triangle

27=1/2 * x*x+3

27=(x sq +3)/2

27*2=x sq +3

54=x sq +3

hope it will help you :)

mark it as brainliest

Answer 2

Answer:

GIVEN- AREA=27 SQCM

PERPENDICULAR IS 3CM

LET THE BASE BE-X CM

3+X CM

Step-by-step explanation:

AREA OF RIGHT TRIANGLE-HALF * BASE *HEIGHT

A/Q

27=half *(3+x)*3

54= 9+3x

54-9=3x

5=3x

x=5/3

it may help you!!!