Question

2. The area of a square 1600 m² Find the area of a
rectangle whose breadth is the same as that of
the square and length is 10 m more than its
breadth.​

Answer 1

Answer:

Sides of square will be √1600 = 40 m

So new rectangle will have breadth 40 and

length 10 more or = 40 + 10 = 50 m

So it's area = 40× 50 = 2000 sq.m

Answer 2

$Area \: of \: square \: = 1600 \: {m}^{2} \\ Side \: of \: square = \sqrt{area} = \sqrt{1600} = 40 \: m \\ Breadth \: of \: rectangle = 40 \: m \\ Length \: of \: rectangle = 40 + 10 = 50 \: m \\ Area \: of \: rectangle = l \times b = 40 \times 50 = 2000 \: {m}^{2}$