2. The area of cross-section of an iron plate of thickness
2 cm is 5000 cm². The temperatures of its surfaces
are 150°C and 140°C respectively. Calculate the rate
of heat transmitted through this plate. Coefficient of
thermal conductivity of iron is 0.015 kcal s-1 m-ldegree c-1.
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Answer:
-350kcal/m2
Explanation:
Q=-kAdT/dX
Q=-[0.015×5000×10]÷2
Q=-[750]÷2
Q=-350kcal/m2
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