Question

2. The atomic number of beryllium is 4 while that of oxygen is 8.
Write down the electronic configuration of the two and deduce
their valency from the same.​

Answer 1

$\huge\mathfrak{Answer:-}$

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Oxygen (Atomic number= 8)

• Electronic configuration = 2, 6
• Since 2 electrons are required to complete the octet, the valency of oxygen is 2.

Beryllium (Atomic number= 4)

• Electronic configuration= 2,2
• Since it has 2 electrons in outermost shell it's valency is 2.

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Answer 2

Answer:

Explanation:

Atomic number of Beryllium = 4

Electronic configuration = (2, 2)

Atomic number of Oxygen = 8

Electronic configuration = (2, 6)

Valency of Beryllium is 2,

Valency of Oxygen is = 8 ‒ 6 = 2