Question

2. The atomic number of beryllium is 4 while that of oxygen is 8.
Write down the electronic configuration of the two and deduce
their valency from the same.​

Answer 1

Answer:

electronic configuration of beryllium=2,2

2 electrons are in the outermost shell so to complete its duet it will donait 2 electrons.

hence its valency is 2

electronic configuration of oxygen=2,6

6 electrons are in the outermost shell and to complete its octet it needs 2 electrons.

hence its valency is -2.

hope it helps you

Answer 2

Answer:

beryllium the k shell can hold a maximum of to electrons so other 2 electrons move in l shell the l shell capacity is 8 so be will give out 2 electrons to be duplet while o will take in 2 to be octet

Explanation:

MARK ME BRAINLIEST

so be is 2 while o is -2