Question

2. The base of right triangle is 8 cm and
hypotenuse is 10 cm. Its area will be
(b) 40 cm2
(d) 80 cm?
(a) 24 cm2
(c) 48 cm
2
richt
ninle
C
2​

Answer 1

Answer:

24 cm²

Step-by-step explanation:

base = 8cm

hypotenuse = 10

perpandicular = 10² - 8²

= √36 = 6

Area of triangle = 1/2 b× h

= 1/2 8×6

= 4×6

= 24 cm²

Answer 2

★GIVEN★

• The base of right triangle is 8 cm
• Hypotenuse is 10 cm.

★To Find★

The area.

★SOLUTION★

It said to be a right angled triangle.

The base is not given.

So by using Pythagoras Theorem we can find the base.

By Pythagoras Theorem,

$\large{\green{\underline{\boxed{\bf{(Hypo)^2=(Base)^2+(side)^2}}}}}$

where,

• Hypo = Hypotenuse = 10 cm.
• Side = 8 cm. (height)
• Base = b cm.

According to the question,

$\large\implies{\sf{(Hypo)^2=(Base)^2+(side)^2}}$

Putting the values,

$\large\implies{\sf{(10)^2=(b)^2+(8)^2}}$

$\large\implies{\sf{100=(b)^2+64}}$

$\large\implies{\sf{100-64=(b)^2}}$

$\large\implies{\sf{36=(b)^2}}$

Square rooting both the sides,

$\large\implies{\sf{\sqrt{36}=b}}$

$\large\implies{\sf{\frac{+}{-}6=b}}$

$\large\therefore\boxed{\bf{Base=\frac{+}{-}6\:cm.}}$

We have got the base.

So, now we can find area of the triangle.

We know that,

$\large{\green{\underline{\boxed{\bf{Area=\dfrac{1}{2}\times\:base\times\:height}}}}}$

where,

• Base = 6 cm.
• Height = 8 cm.

Putting the values,

$\large\implies{\sf{Area=\dfrac{1}{2}\times6\times8}}$

$\large\implies{\sf{Area=\dfrac{1}{\cancel{2}}\times\cancel{6}\times8}}$

$\large\implies{\sf{Area=1\times3\times8}}$

$\large\therefore\boxed{\bf{Area=24\:cm^2.}}$

Area of the triangle is 24 cm².

So, your answer is option (a).