2. The cable of a suspension bridge hangs in the shape of a parabola. The
towers supporting the cable are 400 ft apart and 150 ft high. If the cable,
at its lowest, is 30 ft above the bridge at its midpoint, how high is the cable
50 ft away (horizontally) from either tower?
(200, 150)
Answers
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Answer:
= 0, y = 20
x = -600, y = 170
x = +600, y = 170
using the form ax^2 + bx + c = y, we know that c=20
x=-600, y = 170 and x =+600, y = 170; write two equations
-600^2a - 600b + 20 = 170
+600^2a + 600 + 20 = 170
use elimination
360000a - 600b + 20 = 170
360000a + 600b + 20 = 170
------------------------------addition eliminates b
720000a + 40 = 340
720000a = 300
a = 300/720000
a = .0004167
Now we can write the equation
y = .0004167x^2 + 20
Graphically
Step-by-step explanation:
Hope I help you!!
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