Question

2. The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys another
bat and 3 more balls of the same kind for? 1300. Represent this situation algebraically
and geometrically​

Answer 1

Answer:

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Step-by-step explanation:

let rate of bat = xRs.

and rate of ball = yRs.

3x+6y=3900.....(i)

and x+3y=1300.....(ii)

or x=(1300−3y)

now equation (i) can be written as

3(1300−3y)+6y=3900

3900−9y+6y=3900

∴y=0

Ans:- x=1300

solution