Question

2. The cost of 8 tables is equal to the selling price of 6 tables. Find the gain
percent.​

Answer 1

Answer:

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Answer 2

$\large\underline{\bf{Solution-}}$

Let

• Cost Price of 1 table = Re 1

So,

• Cost Price of 6 tables = Rs 6

and

• Cost Price of 8 tables = Rs 8

According to statement,

Selling Price of 6 tables = Cost Price of 8 tables

It implies,

• Selling Price of 6 tables = Rs 8

Now we have,

• Selling Price of 6 tables = Rs 8

• Cost Price of 6 tables = Rs 6

Since,

• Selling Price > Cost Price

So,

• There is gain in this transaction.

We know,

$\rm :\longmapsto\:Gain = Selling \: Price - Cost \: Price$

$\rm :\longmapsto\:Gain = 8 - 6$

$\bf\implies \:Gain = Rs \: 2$

Now,

$\rm :\longmapsto\:Gain\% = \dfrac{Gain}{Cost \: Price} \times 100\%$

$\rm :\longmapsto\:Gain\% = \dfrac{2}{6} \times 100\%$

$\bf\implies \:Gain\% = \dfrac{100}{3}\% = 33\dfrac{1}{3}\%$

$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain \%) \: (or)(100 - Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$