Question

2
The depression in the freezing point of a solution is 0.48 K. Hence the concentration of the solution is
(K = 2.4 km)
(1) 5 m
(2) 0.2 m
(3) 2.88 m
(4) 1.152 m

please answer fast​

Answer 1

Answer:

ΔT

f

=0.24k mass of KCl=1g Kf=1.86K kg/mol

mass of water (solvent) =200g

Molar mass of solute =

ΔT

1

×mass of solvent

1000×Kf×mass of ssolut=

0.24×200

1000×1.86×1

=38.75g/mol

This is the experimental molar mass of solute (KCl).

Theoretical molar mass =3a+35.5=74.5g/mol

van't hott factor (i) =

Expermenmtal molar mass

Theoretical molar mmas=

38.75

74.5

∴i=1.92