Question

2. The diagram given below shows two paths
drawn inside a rectangular field 50 m long and
35 m wide. Find the area of the shaded portion.
k - 50 m
35 m
5 m
5 m
don't delay please nead now​

Answer 1

Answer:

400 m

Step-by-step explanation:

Length of rectangle ABCD =50 m

Breadth of rectangle ABCD =5 m

Area of rectangle ABCD =L×B

                                        =50×5

                                        =250 m  

2

 

Length of rectangle EFGH =35 m

Breadth of rectangle EFGH =5 m

Area of rectangle EFGH =35×5

                                        =175 m  

2

 

Length of rectangle ILKL =5 m

Breadth of rectangle IJKL =5 m

Area of rectangle IJKL =35×5

                                        =175 m  

2

 

Now,

Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL

                                      =(250+175)−25

                                      =425−25

                                      =400 m  

2

 

Hence area of shaded portion is 400 m  

Answer 2

Length of rectangle ABCD =50 mBreadth of rectangle ABCD =5 mArea of rectangle ABCD =L×B =50×5 =250 m Length of rectangle EFGH =35 mBreadth of rectangle EFGH =5 mArea of rectangle EFGH =35×5 =175 m Length of rectangle ILKL =5 mBreadth of rectangle IJKL =5 mArea of rectangle IJKL =35×5 =175 m Now,Area of shaded portion = (Area of ABCD + Area of EFGH) − Area of IJKL =(250+175)−25 =425−25 =400 m Hence area of shaded portion is 400 m

Hope it helps you bro!!!