Question

2. The difference between the compound interest and the simple interest on 42000 for
two
years
is 105 at the same rate of interest per annum. Find
(i) the rate of interest
(ii) the compound interest earned in second year.​

Answer 1

Answer:

P = Rs 42000 T=2 years

Let rate = r %

S.I=

100

PRT

=

100

42000×r×2

=840 Rs

For C.I

A=P(1+

100

r

)

n

=42000(1+

100

r

)

2

=42000(1+

10000

r

2

+

50

r

)

=42000+

10

42r

2

+840r

C.I = A - P

=42000+

10

42r

2

+840r−42000

=

10

42r

2

+840r

Given C.I−S.I=105

=

10

42r

2

+840r−840r=105

=

10

42r

2

=105

=42r

2

=1050

=r

2

=25

r=5%

C.I at 2nd year = 42000(1+

100

5

)

2

−42000

=42000(1.1025−1)=4305 Rs

solution

Step-by-step explanation:

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