Question

2.
The distance between the two charges 25 uC and 36 uC is 11 cm. At what point on the line joining
the two, the intensity will be zero ?
(1) At a distance of 5 cm from 25 C
(2) At a distance of 5 cm from 36 uc
(3) At a distance of 4 cm from 25 uC
(4)
At a distance of 4 cm from 36 uc


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Answer 1

two charges $25\mu C$ and $36\mu C$ are situated 11cm apart from each other. Let a point P, on line the two charges, distance from charge $25\mu C$ is x cm, where electric field intensity becomes zero.

means, electric field intensity due to $25\mu C$ at P = electric field intensity due to $36\mu C$

or, k($25\mu C$)/x² = k($36\mu C$)/(11 - x)²

or, 25/x² = 36/(11 - x)²

or, 5²/x² = 6²/(11 - x)²

or, 5/x = 6/(11 - x)

or, 5(11 - x) = 6x

or, 55 = 11x => x = 5cm

hence, the point is located at a distance 5cm from $25\mu C$

hence, option (a) is correct

Answer 2

Answer:

.option (1) is correct.