Question

2.the distance covered by a car in 5th second moving with an acceleration 2m/s² from rest. [ ] a. 9m b. 21m c. 19m d. 10m

Answer 1

Explanation:

hi frnd

initial velocity u=+9m/s ;

acceleration a =-2m/s²

in this problem,acceleration's direction is opposite to the velocity's direction

let 't' be the time taken by the particle to, reach a point where it makes a turn along the straight line.

we have,v=u+at

0=9+2t

we get,t=4.5sBrainly – Homework Help App

now let us find the distance covered in 1/2 second i.e..,from 4.5 to 5 second

let u=0at t=4.5 second

then distance covered in 1/2 s

we have,v=u+at

total distance covered in fifth second of its motion is given by s=2s=2(1/4)=0.5m

which is equal to 1/4

I believe this will help u :)