Question

2. The domain of sin2x is () (b) [-1,1] (d) / (-2,2. (a) [0,1] :'2​

Answer 1

Answer:

f(x)=sin

−1

(2x)

domain of sin

−1

x is xϵ[−1,1]

So, for f(x),

−1≤2x≤1

⇒

2

−1

≤x≤

2

1

∴xϵ[−

2

1

,

2

1

]