2
the eigen
values of adjA & Of A² - 2A +I
find A=[234
042
003]
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Answer:
Step-by-step explanation:
Given, A
2
=2A−I ...(i)
On multiplying by A both sides, we get
A
2
⋅A=(2A−I)A
⇒A
3
=2A
2
−IA
=2(2A−I)−IA [from equation (i)]
=4A−2I−A .....(∵IA=A)
=3A−2I
Similarly, A
4
=4A−3I
⇒A
5
=5A−4I
Hence, A
n
=nA−(n−1)I
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