Question

2) the eq of the straight line passing through the point (4,3) and making the intercept on the coordinate axes whose sum is -1 is

Answer 1

Solution:-

given by:- the eq of the straight line passing through the point (4,3)

》form of intercept :-
》4/a + 3/b = 1...........(1)

》Sum of intercepts = -1
》a+ b = -1

from eq (1) .
》4b + 3a = ab
》3a+3b + b = ab
》3×(-1) + b = ab , [ a = -1-b]
》-3 + b = - b - b^2
》b^2+2b-3 = 0
》b(b+3)-1(b-3)=0
》(b+3)(b-1) =0

》b = (1 , - 3)
》a.= ( -2 , 2)

》point :- ( -2 ,1) and ( 2, -3)

》line:- x/-2 + y/1 = 1 , x/2 + y/-3 = 0

☆i hope its help☆