Question

2. The equation of the normal to the curve y = sin x at (0, 0) is
(a) x = 0
(b) y = 0
(c) x + y = 0
(d) x – y = 0

Answer 1

Answer:

$this \: is \sin(x) at \frac{0}{0} this \: is \: your \: question$

$i \: hope \: it \: helps \:$

$please \: mark \: and \: rated \: me$

Answer 2

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Given that, y = sin x

Hence, dy/dx = cos x

Thus, the slope of the normal = (-1/cos x)x =0 = -1

Therefore, the equation of the normal is y-0 = -1(x-0) or x+y=0

Hence, the correct solution is option c

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Hope it's Helpful.....:)