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2 The fifth team of an Ap is 17 and
its twelth terms exceeds its seventh term by 15 find common different and the first term
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Answer:
a5=17
a+4d=17................(1)
a12=a7+15
a+11d=a+6d+15
a+11d-a-6d=15
5d=15
d=3
From eq. (1)
a+4d=17
a+(4*3)=17
a+12=17
a=5
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