Question

2. The focal length of a concave mirror is
15 cm. If the object distance is 20 cm, find the
position and nature of the image.
(Ans. U= -60 cm. The image is real, inverted
and magnified.)
with steps​

Answer 1

HEYA MATE

HERE IS UR ANSWER

u (object distance) =-20cm

f (focal length) =-15 cm

put values in mirror formula :-

1/f=1/u+1/v

1/v=1/f-1/u

1/v=1/-15 +1/-(-20)

1/v=1/-15+1/20

by taking LCM

1/v=-1/60

v=-60

HENCE PROVED

m (magnification) =-v/u

m=-(-60)/-20

m=-3

#IMAGE IS REAL AND INVERTED #

HEYA MATE ALSO REMEMBER

NMR =NEGATIVE MAGNIFICATION REAL AND INVERTED

PMV =POSITIVE MAGNIFICATION VIRTUAL AND ERRECT

HOPE IT HELPED

MARK AS BRAINLIEST

Answer 2

F=15

Then c=30

If u=20, then the object placed between c and f.

As per your condition u= - 60 cm but it is wrong, v =-60 cm

Let's check it

1/f=1/v-1/u

1/15=1/v-1/-20

1/15-1/20=1/v

20-15/300=1/v

5/300=1/v

1/60=1/v

V=60 cm the image formed at the same side of the mirror

Therefore v=-60 cm

Then u<v therefore enlarged image and real inverted