Math, asked by sahilbhat0523, 9 months ago

2. The following numbers are obviously not perfect squares. Give reason.
(1) 1057 (ii) 23453
(iii) 7928
(iv) 222222
(v) 64000 (vi) 89722 (vii) 222000 (viii) 505050​

Answers

Answered by AakritiBansal02
10

Step-by-step explanation:

1. it contains 7 in the end.

2. it contains 3 in the end .

3. it contains 8 in the end .

4. it contains 2 in the end .

5. it contains three zeroes in the end .

6. it contains 2 in the end .

7. it contains three zeros in the end.

8. it contains one zero in the end.

Answered by Anonymous
85

\huge{\fcolorbox{skyblue}{black}{\huge{\fcolorbox{red}{yellow}{{\fcolorbox{purple}{pink}{Answer}}}}}}

(i) 1057 ends with 7 at unit place. So it is not a perfect square number.

(ii) 23453 ends with 3 at unit place. So it is not a perfect square number.

(iii) 7928 ends with 8 at unit place. So it is not a perfect square number.

(iv) 222222 ends with 2 at unit place. So it is not a perfect square number.

(v) 64000 ends with 3 zeros. So it cannot a perfect square number.

(vi) 89722 ends with 2 at unit place. So it is not a perfect square number.

(vii) 22000 ends with 3 zeros. So it can not be a perfect square number.

(viii) 505050 ends with 1 zero. So it is not a perfect square number.

Similar questions