Math, asked by thakurseema101981, 5 months ago

2. The following numbers are obviously not perfect squares. Give reason.
(1) 1057
() 23453 (ii) 7928
(iv) 222222
(v) 64000 (vi) 89722 (vii) 222000
(viii) 505050​

Answers

Answered by mama1015
4

Answer:

1)1057 is not a perfect square because since the number is ending digit is 7 (which is not one of 0,1,4,5,6 or 9)

2)7928 is not a perfect square because it ends with 8 whereas the square numbers end with 0,1,4,5,6 or 9. 4)222222 is not a perfect square because it ends up with 2 whereas square ends with 0,1,4,5,6 or 9.

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Answered by BlessedMess
89

We know that natural numbers ending in yhe digits 0,2,3,7 and 8 are not perfect squares.

(i) 1057 \longrightarrow ends with 7

(ii) 23453 \longrightarrow ends with

(iii) 7928 \longrightarrow ends with 8

(iv)222222 \longrightarrow ends with 2

(v)64000 \longrightarrow ends with 0

(vi) 89722 \longrightarrow ends with 2

(vii) 222000 \longrightarrow ends with 0

(viii) 505050 \longrightarrow ends with 0

So,the following numbers are obviously not perfect square.

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