Question

2. The H.C.F of two numbers is 15 and their L.C.M is 180. If one of the
numbers is 45 find the other number.​

Answer 1

$\large{\underline{\boxed{ Answer}}}$

H. C. F = 15

L. C. M = 180

Let the two numbers be "a" and "b" .

Now the relation between the H. C. F and L. C. M and product of two number is given by :-

$\boxed{\sf{</strong><strong>H</strong><strong>.</strong><strong>C</strong><strong>.</strong><strong>F</strong><strong> </strong><strong>×</strong><strong> </strong><strong>L</strong><strong>.</strong><strong> </strong><strong>C</strong><strong>.</strong><strong> </strong><strong>M</strong><strong> </strong><strong>=</strong><strong> </strong><strong>a</strong><strong> </strong><strong>×</strong><strong> </strong><strong>b</strong><strong>}}$

$= > 15 \times 180 = 45 \times b$

$= > 2700 = 45 \times b$

$= > b = \frac{2700}{45}$

$= > b = 60$

hence, second number will be = 60

Answer 2

Answer:

given,

H.C.F = 15

L.C.M=180

one number =180

find the other number =x

HCF*LCM= products of two number

15*180=45*x

2,700/45=x

60

so second number is 60

hope you understand

plz mark brainliest.